Determining g with an Atwood Machine
Time a known drop of the heavier mass at several mass ratios. Recover a = 2s/t² and fit a versus (m₁−m₂)/(m₁+m₂) to get g.
Goal
Determine g from timed Atwood runs: acceleration a = 2s/t² from rest, then the slope of a versus (m₁−m₂)/(m₁+m₂) equals g.
Equipment
- Atwood pulley (massless)
- Masses m₁, m₂
- Metre scale (drop s)
- Stopwatch
Experiment
Theory
For a massless frictionless pulley, a = g (m₁−m₂)/(m₁+m₂). From rest, s = a t²/2 so a = 2s/t². Plotting a against x = (m₁−m₂)/(m₁+m₂) is a straight line through the origin with slope g. The bench hides a and the string tension; you only time the drop.
Procedure
- m₂ and the drop distance s are fixed and known. You only change the heavier mass m₁.
- Release from rest and record the stopwatch time t for the drop. Small timing noise is added.
- The notebook computes a = 2s/t² and x = (m₁−m₂)/(m₁+m₂).
- Repeat for at least 6 different m₁ values spread across the slider range.
- Fit a versus x; the slope is g. Compare with the reference 9.81 m/s².
Conclusion
The fitted g agrees with standard gravity within tolerance. Main uncertainties: stopwatch noise, a massless frictionless pulley, and treating the drop as uniformly accelerated from rest.