Determining g with an Atwood Machine

Time a known drop of the heavier mass at several mass ratios. Recover a = 2s/t² and fit a versus (m₁−m₂)/(m₁+m₂) to get g.

Kids· 22 min·Related simulator: Classical MechanicsAtwood Machine

Goal

Determine g from timed Atwood runs: acceleration a = 2s/t² from rest, then the slope of a versus (m₁−m₂)/(m₁+m₂) equals g.

Equipment

  • Atwood pulley (massless)
  • Masses m₁, m₂
  • Metre scale (drop s)
  • Stopwatch

Experiment

Theory

For a massless frictionless pulley, a = g (m₁−m₂)/(m₁+m₂). From rest, s = a t²/2 so a = 2s/t². Plotting a against x = (m₁−m₂)/(m₁+m₂) is a straight line through the origin with slope g. The bench hides a and the string tension; you only time the drop.

Procedure

  1. m₂ and the drop distance s are fixed and known. You only change the heavier mass m₁.
  2. Release from rest and record the stopwatch time t for the drop. Small timing noise is added.
  3. The notebook computes a = 2s/t² and x = (m₁−m₂)/(m₁+m₂).
  4. Repeat for at least 6 different m₁ values spread across the slider range.
  5. Fit a versus x; the slope is g. Compare with the reference 9.81 m/s².

Conclusion

The fitted g agrees with standard gravity within tolerance. Main uncertainties: stopwatch noise, a massless frictionless pulley, and treating the drop as uniformly accelerated from rest.