- Why does the oscillation amplitude eventually become constant, even with damping?
- The damping force continuously dissipates energy, but the external driving force does work on the system, inputting energy. After an initial transient period, a balance is reached where the energy input per cycle from the driver exactly equals the energy lost per cycle to damping. This results in a steady-state oscillation with constant amplitude.
- What is the difference between the natural frequency and the resonant frequency?
- The natural frequency, ω₀ = √(k/m), is the frequency at which the system would oscillate if there were no damping or driving force. The resonant frequency, ω_r, is the driving frequency at which the steady-state amplitude is maximum. For light damping, ω_r is very close to ω₀, but for heavier damping, ω_r is slightly lower than ω₀.
- How does increasing the damping affect the resonance curve?
- Increasing the damping coefficient (b) broadens the resonance peak and reduces its maximum height. A heavily damped system has a large range of driving frequencies that produce a significant response, but the maximum amplitude at resonance is much smaller. In contrast, light damping produces a very tall, narrow peak, indicating a more selective and dramatic resonance.
- Can this model describe a child being pushed on a swing?
- Yes, it's an excellent analogy. The swing is the oscillator (with a natural frequency), air resistance provides damping, and the pushes are the periodic driving force. To maximize amplitude (resonance), you must push at the swing's natural frequency. The model simplifies the push to a perfect cosine force, whereas a real push is a brief impulse, but the overall resonance phenomenon is the same.