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Home/Engineering/Planar Truss (triangle)

Planar Truss (triangle)

Symmetric 3-bar truss: bar forces and reactions vs span, height, and apex load.

Geometry & load

2.4
1.35
8

Statically determinate 3-bar triangle: method of joints gives equal forces in the sloping members; the base chord is unloaded for this symmetric vertical load. Pin at B, roller at C — reactions split P/2 each.

Measured values

Force ABC 5.35
Force ACC 5.35
Force BCT 0.00
R_By4.00
R_Cy4.00

About this model

A planar truss is a fundamental structural system in engineering, composed of slender members connected at pin joints. This simulator focuses on the simplest stable configuration: a symmetric three-bar triangular truss, often called a 'simple truss' or 'triangle truss.' It is loaded by a single downward force at its apex. The model calculates and visualizes the internal axial forces within each member and the support reactions at the two base pins. The core physics is governed by static equilibrium, applying Newton's First Law: for the entire structure to be stationary, the sum of all forces in any direction and the sum of all moments must equal zero. By isolating the apex joint as a free body, we can use the equations ΣFx = 0 and ΣFy = 0 to solve for the forces in the two sloping members. The geometry, defined by the span (horizontal distance between supports) and height (vertical distance from the supports to the apex), directly influences these forces through trigonometric relationships. For example, the force in a sloping member is proportional to the applied load and inversely proportional to the sine of its angle from the horizontal (F = P / (2 sin θ)). The horizontal base member (the tie) experiences a compressive or tensile force found from horizontal equilibrium. Key simplifications include assuming weightless members, perfect pin joints (which cannot transmit moments), and a structure that is initially stress-free and perfectly rigid. Interacting with this simulator teaches core concepts of static determinacy, force resolution, and how structural geometry dictates load paths, providing an intuitive foundation for more complex truss analysis.

Who it's for: High school physics and introductory undergraduate engineering students (e.g., statics, civil engineering, or architecture) learning the principles of static equilibrium and truss analysis.

Key terms

  • Static Equilibrium
  • Truss
  • Axial Force
  • Reaction Force
  • Free Body Diagram
  • Pin Joint
  • Determinate Structure
  • Resolution of Forces

How it works

A minimal introduction to bar axial forces before larger trusses and Cremona diagrams. Sloping members here carry compression for a downward apex load (C = compression, T = tension magnitude).

Frequently asked questions

Why are the members assumed to be connected by 'pin joints'?
Pin joints are a standard simplification in basic truss analysis. They allow members to rotate freely, meaning they can only transmit force along their axis (tension or compression), not bending moments. This assumption turns each member into a 'two-force member,' greatly simplifying the calculations. Real-world connections (like welded or bolted joints) are more rigid but are often modeled as pins for initial design analysis.
What happens to the forces in the bars if I make the truss very flat (small height)?
As the truss becomes flatter, the angle of the sloping bars decreases. Since the internal force is inversely proportional to the sine of this angle, the forces become very large. This demonstrates a critical engineering principle: shallow trusses require much stronger (and often heavier) members to carry the same load, which is why bridges and roofs have significant height for their span.
Is the bottom horizontal member always in tension?
For the symmetric downward load at the apex shown, yes. The sloping members push inward and downward on the apex. Their horizontal components push outward on the supports. The horizontal tie member is needed to pull the supports back together, placing it in tension. If the load direction or position changed, this member could go into compression.
Can this truss support a load placed somewhere other than the apex?
This specific three-bar, simply supported triangular truss is statically determinate only for loads applied at the joints. The model simplifies by only allowing a load at the apex joint. A load applied elsewhere along a member would introduce bending, violating the 'two-force member' assumption and requiring a more advanced analysis (treating the member as a beam).