If a small gear drives a large gear, does the output spin faster or slower?

It spins slower. The output speed (angular velocity) is inversely proportional to the ratio of teeth. A large gear has more teeth, so for every full rotation of the small driver gear, the large driven gear only completes a fraction of a rotation. This speed reduction comes with a proportional increase in output torque.

Why is the torque multiplied when speed is reduced? Where does the 'extra' torque come from?

The 'extra' torque doesn't come from nowhere; it's a trade-off governed by energy conservation. In an ideal gear train, input power (Torque * Speed) equals output power. If the speed decreases, the torque must increase to keep the power product constant. The gear system transforms the input force into a higher output force over a shorter rotational distance.

Do real gear trains behave exactly like this ideal model?

No, this is a simplified, ideal model. Real gears have friction, which dissipates energy as heat, so output power is always less than input power. They also have inertia (resistance to acceleration) and backlash (a slight gap between teeth), which affect dynamic performance and precision. The core ratios, however, remain the primary design guide.

What is a compound gear train, and why is it used?

A compound gear train uses one or more intermediate shafts with two gears fixed together. This allows for much larger overall gear ratios in a compact space than a simple train of the same size. The total ratio is found by multiplying the ratios of each meshing pair along the power path.

Gear Train

Connect gears, adjust teeth count, see speed and torque ratios.

About this model

Gear trains are fundamental mechanical systems that transmit rotational motion and torque between shafts. This simulator models the kinematics and kinetics of simple and compound gear trains, where gears are represented as perfect circles with teeth around their circumference. The core principle is the conservation of angular displacement at the point of contact: for two meshing gears, the number of teeth passing that point per unit time must be equal. This leads directly to the gear ratio, defined as (N_driven / N_driver), where N is the number of teeth. The angular velocity ratio (ω_out / ω_in) is the inverse of this tooth count ratio, while the torque ratio (τ_out / τ_in) is directly proportional to it, assuming an ideal, lossless system (τ_out / τ_in = N_driven / N_driver). This trade-off between speed and torque is a direct consequence of the conservation of energy for a static system (Power_in = Torque_in * ω_in = Torque_out * ω_out = Power_out). The model simplifies real-world complexities by ignoring friction, inertia, backlash, tooth profile geometry, and material deformation. By connecting gears and adjusting their tooth counts, students can visually explore and quantitatively verify these fundamental relationships, solidifying their understanding of rotational kinematics, mechanical advantage, and energy transfer in a highly configurable system.

Who it's for: High school physics and introductory engineering students studying rotational motion, as well as vocational/technical students learning the principles of mechanical power transmission.

Key terms

Gear Ratio
Angular Velocity
Torque
Mechanical Advantage
Kinematics
Power Transmission
Compound Gear Train
Conservation of Energy

How it works

A serial gear train: neighboring gears mesh, so line speed at the pitch circle matches. Angular speeds satisfy ωᵢ₊₁ = −ωᵢ (Tᵢ/Tᵢ₊₁). Intermediate tooth counts cancel in the overall speed ratio: |ω_out/ω_in| = T_first/T_last. For ideal power (no slip, no losses), τ_out/τ_in ≈ T_last/T_first — trade speed for torque.

Key equations

ωᵢ₊₁ = −ωᵢ · (Tᵢ / Tᵢ₊₁), P = τω ≈ const

Frequently asked questions

If a small gear drives a large gear, does the output spin faster or slower?: It spins slower. The output speed (angular velocity) is inversely proportional to the ratio of teeth. A large gear has more teeth, so for every full rotation of the small driver gear, the large driven gear only completes a fraction of a rotation. This speed reduction comes with a proportional increase in output torque.
Why is the torque multiplied when speed is reduced? Where does the 'extra' torque come from?: The 'extra' torque doesn't come from nowhere; it's a trade-off governed by energy conservation. In an ideal gear train, input power (Torque * Speed) equals output power. If the speed decreases, the torque must increase to keep the power product constant. The gear system transforms the input force into a higher output force over a shorter rotational distance.
Do real gear trains behave exactly like this ideal model?: No, this is a simplified, ideal model. Real gears have friction, which dissipates energy as heat, so output power is always less than input power. They also have inertia (resistance to acceleration) and backlash (a slight gap between teeth), which affect dynamic performance and precision. The core ratios, however, remain the primary design guide.
What is a compound gear train, and why is it used?: A compound gear train uses one or more intermediate shafts with two gears fixed together. This allows for much larger overall gear ratios in a compact space than a simple train of the same size. The total ratio is found by multiplying the ratios of each meshing pair along the power path.

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How it works

Key equations

Frequently asked questions