Weak-Acid Titration: pK_a at Half-Equivalence

Weak acid + strong base. Find V_eq from the pH jump, then read pH at V_b = V_eq/2. That pH is pK_a.

School· 24 min·Related simulator: ChemistryTitration Simulator

Goal

Determine pK_a from Henderson–Hasselbalch: at half-equivalence [A⁻]=[HA], so pH = pK_a.

Equipment

  • Burette (known C_b)
  • Flask (known V_a, unknown HA)
  • pH meter
  • Universal indicator

Experiment

Theory

For a monoprotic weak acid titrated with strong base, the buffer region has pH = pK_a + log₁₀([A⁻]/[HA]). Halfway to equivalence, half the acid is neutralized, so the ratio is 1 and pH = pK_a. Equivalence itself is basic (the conjugate base hydrolyzes) — do not read pK_a there. The bench never prints pK_a, V_eq, or a Henderson hint.

Procedure

  1. Aliquot V_a and titrant C_b are fixed and known. Acid concentration and pK_a are hidden. You only change the burette V_b.
  2. Watch the live pH meter and indicator. Find the jump (equivalence), note that V_eq, then set V_b = V_eq/2.
  3. Record. The row stores V_b and the pH. Small meter noise is added. The bench does not mark half-equivalence.
  4. Repeat the half-equivalence reading at least 6 times (re-find the jump if you like).
  5. Take the mean of the pH column. Compare with the reference pK_a.

Conclusion

The mean pH at half-equivalence agrees with the hidden pK_a. Main uncertainties: judging V_eq by eye, meter noise, and the ideal Henderson–Hasselbalch buffer.