Weak-Acid Titration: pK_a at Half-Equivalence
Weak acid + strong base. Find V_eq from the pH jump, then read pH at V_b = V_eq/2. That pH is pK_a.
Goal
Determine pK_a from Henderson–Hasselbalch: at half-equivalence [A⁻]=[HA], so pH = pK_a.
Equipment
- Burette (known C_b)
- Flask (known V_a, unknown HA)
- pH meter
- Universal indicator
Experiment
Theory
For a monoprotic weak acid titrated with strong base, the buffer region has pH = pK_a + log₁₀([A⁻]/[HA]). Halfway to equivalence, half the acid is neutralized, so the ratio is 1 and pH = pK_a. Equivalence itself is basic (the conjugate base hydrolyzes) — do not read pK_a there. The bench never prints pK_a, V_eq, or a Henderson hint.
Procedure
- Aliquot V_a and titrant C_b are fixed and known. Acid concentration and pK_a are hidden. You only change the burette V_b.
- Watch the live pH meter and indicator. Find the jump (equivalence), note that V_eq, then set V_b = V_eq/2.
- Record. The row stores V_b and the pH. Small meter noise is added. The bench does not mark half-equivalence.
- Repeat the half-equivalence reading at least 6 times (re-find the jump if you like).
- Take the mean of the pH column. Compare with the reference pK_a.
Conclusion
The mean pH at half-equivalence agrees with the hidden pK_a. Main uncertainties: judging V_eq by eye, meter noise, and the ideal Henderson–Hasselbalch buffer.