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Home/Electricity & Magnetism/Hall Effect

Hall Effect

The Hall Effect describes the generation of a transverse voltage, the Hall voltage (U_H), across a current-carrying conductor placed in a perpendicular magnetic field. This simulator visualizes the underlying physics: a steady current (I) flows through a rectangular slab of material. A uniform magnetic field (B) is applied perpendicular to the slab. The magnetic Lorentz force (F = q(v × B)) deflects the moving charge carriers—either electrons or positively-charged 'holes'—towards one side of the slab. This charge separation creates an internal electric field (E_H) that opposes further deflection. At equilibrium, the electric force balances the magnetic force, resulting in a measurable Hall voltage. The core relationship is given by U_H = R_H * (I * B) / t, where t is the thickness of the slab and R_H is the Hall coefficient. Crucially, R_H = 1/(n q), where n is the charge carrier density and q is their charge. The sign of R_H (and thus the polarity of U_H) reveals whether the dominant carriers are negative (e.g., electrons, q = -e) or positive (holes, q = +e). The simulator simplifies by assuming a uniform, rectangular conductor with perfectly aligned fields, negligible temperature effects on carrier mobility, and an idealized geometry where the Hall voltage contacts are precisely at the edges. By manipulating the magnetic field strength, current, material type (n-type or p-type semiconductor), and slab thickness, students can explore how each parameter influences the Hall voltage, directly observe the sign reversal for different carrier types, and deduce the carrier density from simulated measurements.

Who it's for: Undergraduate physics and engineering students studying electromagnetism, solid-state physics, or semiconductor device fundamentals.

Key terms

  • Hall Effect
  • Hall Voltage
  • Hall Coefficient
  • Lorentz Force
  • Charge Carrier Density
  • n-type Semiconductor
  • p-type Semiconductor
  • Magnetic Field

Live graphs

Experiment

2.5 A
0.45 T
22 (n in m⁻³)
0.8 µm

Model

U_H = R_H I B / t with R_H = −1/(ne) for electrons and +1/(ne) for holes (single-carrier slab). Sign of U_H (top minus bottom) flips when you switch carrier type or reverse B.

Measured values

U_H (top−bottom)877712213.60µV
R_H (×10⁻⁶ m³/C)-624.151

How it works

When a steady current crosses a conductor in a perpendicular magnetic field, Lorentz force deflects carriers until a transverse Hall field E_H balances it. The Hall voltage U_H is proportional to I and B and inversely proportional to thickness t and carrier density n. The sign of the Hall coefficient R_H distinguishes electron-like and hole-like conduction.

Key equations

U_H = R_H I B / t , R_H = −1/(n e) (e⁻) , R_H = +1/(n e) (holes)
|U_H| ∝ B I / (n t)

Frequently asked questions

Why does the Hall voltage polarity flip when I switch from an 'n-type' to a 'p-type' material?
The polarity depends on the sign of the dominant charge carriers. In n-type materials, electrons (negative charge) are deflected, creating a negative voltage on one side. In p-type materials, holes (effectively positive charge carriers) are deflected in the opposite direction, creating a positive voltage on that same side. The Hall coefficient R_H = 1/(nq) is negative for electrons and positive for holes, causing this flip.
Can the Hall Effect be used for anything practical?
Yes, it has widespread applications. Hall effect sensors are used to measure magnetic field strength (in gaussmeters), detect position and motion (in brushless DC motors and automotive crankshaft sensors), and measure current without physical contact (in current probes). They are fundamental components in many electronic devices.
Why does increasing the slab thickness (t) decrease the Hall voltage in the equation U_H = R_H I B / t?
The Hall voltage is generated across the width of the slab. A thicker slab spreads the same amount of deflected charge over a larger volume, reducing the charge density buildup on the sides. Since the internal electric field (and thus U_H) is proportional to this surface charge density, a greater thickness leads to a smaller voltage for a given current and magnetic field.
Does the Hall Effect occur in insulators or perfect conductors?
No, not in a measurable steady-state form. Insulators lack sufficient free charge carriers to create a significant voltage. In a perfect conductor (zero resistance), the internal electric field must be zero, so the magnetic deflection of charges would be instantly canceled by a rearrangement of surface charges, preventing a stable Hall voltage from developing. The effect is most pronounced and useful in semiconductors and good conductors like metals.